Question

rewrite the following polynomial in standard form.
$-dfrac{x^2}{4} - 1 - 4x$

Explanation:

Step1: Recall standard form of polynomial

The standard form of a polynomial is written in descending order of the exponents of the variable. For a quadratic polynomial in \(x\), the standard form is \(ax^{2}+bx + c\), where \(a\), \(b\), and \(c\) are constants.

Step2: Rearrange the given polynomial

Given the polynomial \(-\frac{x^{2}}{4}-1 - 4x\), we need to rearrange the terms in descending order of the power of \(x\).

The term with \(x^{2}\) is \(-\frac{x^{2}}{4}\), the term with \(x\) is \(- 4x\), and the constant term is \(-1\).

So, rearranging the terms, we get:
\(-\frac{x^{2}}{4}-4x - 1\)

Answer:

\(-\frac{x^{2}}{4}-4x - 1\)