Question

revising an explanation
three complete chemical reactions are given to you, but they are incorrect. you must answer the
questions to correct the equation.
carrie the chemistry teacher poured a solution of sodium chloride into a solution of silver nitrate.
sammy the student was asked to make a prediction regarding the reaction that occurred and provided the
following solution:
(note: ag is always a +1 charge when in a compound.)
nacl(s)+ag(no₃)₂(aq)→agcl(s)+nano₃(aq)
answers
1)___
the formula for sodium chloride is wrong as written: nacl(s)
it should be written as
a. nacl(g)
b. nacl(l)
c. nacl(aq)
2)___
because
a. sodium chloride dissociates in water and becomes aqueous.
b. sodium chloride makes a precipitate in water
c. sodium chloride dissolver in water and becomes liquid
d. sodium chloride makes a precipitate that becomes gaseous in water.
3)___
the formula is wrong for silver nitrate as written: ag(no₃)₂(aq)
it should be written as
a. ag(no₃)₃(aq)
b. ag₂(no₃)₃(aq)
c. ag₃(no₃)₂(aq)
d. agno₃(aq)
4)___
because......
silver makes a(n)
and nitrate makes a(n)
a) 1+ ion
a) 1 - ion
c) 3 - ion
b) 2+ ion
b) 2 - ion
d) 4 - ion
d) 4+ ion

Explanation:

1. Sodium chloride is dissolved in water (as per the problem statement where it's a solution poured), so it should be in aqueous form.
2. When a solid (sodium chloride) is dissolved in water (to form a solution), it dissociates and becomes aqueous.
3. Silver has a +1 charge (given in the note). Nitrate \((NO_3^-)\) has a -1 charge. So the formula for silver nitrate is \(AgNO_3\) (using the criss - cross method: \(Ag^+\) and \(NO_3^-\) combine in 1:1 ratio).
4. Silver (\(Ag\)) has a +1 charge (from the note: \(Ag\) is always a +1 charge when in a compound) and nitrate (\(NO_3^-\)) has a -1 charge.

Answer:

1. c. \(NaCl(aq)\)
2. a. Sodium chloride dissociates in water and becomes aqueous.
3. d. \(AgNO_3(aq)\)
4. a) 1 + ion and nitrate makes a) 1 - ion