Question

reset the objects positions and set their
masses to 1.50 kg. make sure that \elasticity\
remains set to 0%.

in the \more data\ section, click on the velocity
of object 2 and use the onscreen keypad to set
its value to -1.00, the opposite of object 1.
click play to observe the collision and the
resulting velocity of the combined objects.

choose the correct answer from each drop-
down menu to complete the statements.

when the two objects collide, they undergo
drop - down velocity changes. therefore,
the objects experience forces of
drop - down magnitude and
drop - down direction because they have
equal masses and drop - down
accelerations.

Explanation:

1. When two objects collide, their velocities change (so "non - zero" for the first blank as there is a change in velocity).
2. By Newton's third law, the forces between the two objects during collision are equal in magnitude (so "equal" for the second blank).
3. The forces are opposite in direction (Newton's third law, action - reaction pairs), so "opposite" for the third blank.
4. Since \(F = ma\) and \(F\) is equal in magnitude and opposite in direction, and masses are equal, the accelerations are equal in magnitude and opposite in direction (so "equal" for the fourth blank, considering the context of the forces and masses leading to accelerations that are related by \(F = ma\)).

Answer:

• First drop - down: non - zero
• Second drop - down: equal
• Third drop - down: opposite
• Fourth drop - down: equal