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the rectangle to the right has width $5x^{8}$ feet and length $8x^{9}$ …

Question

the rectangle to the right has width $5x^{8}$ feet and length $8x^{9}$ feet. find its area as an expression of x. the area of the rectangle is (simplify your answer.)

Explanation:

Step1: Recall the area formula for a rectangle

The area \(A\) of a rectangle is given by \(A=\text{length}\times\text{width}\). Here, the length \(l = 8x^{9}\) and the width \(w=5x^{8}\).

Step2: Multiply the length and the width

Using the rule of exponents \(a^{m}\times a^{n}=a^{m + n}\) and the commutative property of multiplication \((a\times b)\times(c\times d)=(a\times c)\times(b\times d)\), we have:

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Answer:

\(40x^{17}\) square - feet