Question

a rectangle has an area of 40 square units. the length is 6 units greater than the width. what are the dimensions of the rectangle? \bigcirc 8 by 5 \bigcirc 10 by 4 \bigcirc 11 by 9 \bigcirc 13 by 7

Explanation:

Step1: Check each option's area and length - width difference

For "8 by 5": Area is \(8\times5 = 40\), length - width \(= 8 - 5 = 3
eq6\).

Step2: Check "10 by 4"

Area: \(10\times4 = 40\), length - width \(= 10 - 4 = 6\), matches both conditions.

Step3: Check "11 by 9"

Area: \(11\times9 = 99
eq40\).

Step4: Check "13 by 7"

Area: \(13\times7 = 91
eq40\).

Answer:

B. 10 by 4