Question

in the reaction __h₂ + n₂ → 2 nh₃, what coefficient should be placed in front of h₂ to balance the reaction?

o 1
o 2
o 3
o no coefficient is needed

Explanation:

Step1: Count hydrogen atoms on the right - hand side

In \(2NH_3\), the number of hydrogen atoms is \(2\times3 = 6\).

Step2: Determine the coefficient of \(H_2\)

Let the coefficient of \(H_2\) be \(x\). Since each \(H_2\) molecule has 2 hydrogen atoms, and we need 6 hydrogen atoms (from step 1), we set up the equation \(2x=6\). Solving for \(x\), we get \(x = 3\) (because \(\frac{6}{2}=3\)).

Answer:

3