Question

a raft is crossing a river. the raft is being paddled at a speed of 3 feet per second due east. it is also being carried by the current at a speed of 2.5 feet per second due north of its launching position will the raft be when it reaches the opposite bank? a. 250 b. 300 c. 500 d. 720

Explanation:

Step1: Calculate the time to cross the river

The width of the river is \(d = 600\) feet. The speed of the raft perpendicular to the river (paddling speed) is \(v_y=3\) feet per second. Using the formula \(t=\frac{d}{v_y}\), we have \(t=\frac{600}{3}=200\) seconds.

Step2: Calculate the distance carried by the current

The speed of the current (parallel to the river) is \(v_x = 2.5\) feet per second. Using the formula \(x=v_x\times t\), substitute \(t = 200\) seconds and \(v_x=2.5\) feet per second. So \(x=2.5\times200 = 500\) feet.

Answer:

C. 500