Question

radicals
table for a square root function
fill in the table using this function rule.
$f(x)=\sqrt{x} + 5$
simplify your answers as much as possible.
click
ot a real number\ if applicable.

$x$	$f(x)$
$0$
$16$
$100$

Explanation:

Step1: Evaluate for \( x = -1 \)

The function is \( f(x)=\sqrt{x}+5 \). The square root of a negative number is not a real number, so \( \sqrt{-1} \) is not a real number. Thus, \( f(-1) \) is not a real number.

Step2: Evaluate for \( x = 0 \)

Substitute \( x = 0 \) into \( f(x) \): \( f(0)=\sqrt{0}+5 = 0 + 5 = 5 \).

Step3: Evaluate for \( x = 16 \)

Substitute \( x = 16 \) into \( f(x) \): \( f(16)=\sqrt{16}+5 = 4 + 5 = 9 \).

Step4: Evaluate for \( x = 100 \)

Substitute \( x = 100 \) into \( f(x) \): \( f(100)=\sqrt{100}+5 = 10 + 5 = 15 \).

Answer:

For \( x = -1 \): Not a real number
For \( x = 0 \): \( 5 \)
For \( x = 16 \): \( 9 \)
For \( x = 100 \): \( 15 \)