question 2
which of these is a balanced chemical equation?
2co (g) + 2o₂ (g) → 2co₂ (g)
co (g) + o₂ (g) → co₂ (g)
2co (g) + o₂ (g) → 2co₂ (g)
co (g) + 2o₂ (g) → 2co₂ (g)
question 3
during a chemistry lab exploring chemical reactions, students placed a 30g antacid tablet in a zip - lock bag. then they added 50 grams of water and quickly sealed the bag. the tablet began to fizz and soon disappeared. the bag was filled with gas. how much gas was produced if the mass of the liquid after the reaction is completed is still 50 grams?
50 grams
90 grams
80 grams
30 grams

Question

Accepted Answer

# Explanation:
## Step1: Check the number of atoms for each element in the chemical equation
For $2CO(g)+O_{2}(g)\to2CO_{2}(g)$:
- **Carbon (C)**:
  - Left - hand side: In $2CO$, the number of C atoms is $2\times1 = 2$.
  - Right - hand side: In $2CO_{2}$, the number of C atoms is $2\times1=2$.
- **Oxygen (O)**:
  - Left - hand side: In $2CO$, the number of O atoms from $CO$ is $2\times1 = 2$, and from $O_{2}$ is $2$. So total O atoms $2 + 2=4$.
  - Right - hand side: In $2CO_{2}$, the number of O atoms is $2\times2 = 4$.

For $2CO(g)+2O_{2}(g)\to2CO_{2}(g)$:
- **Oxygen (O)**:
  - Left - hand side: In $2CO$, O atoms from $CO$ is $2\times1=2$, from $2O_{2}$ is $2\times2 = 4$, total $2 + 4=6$.
  - Right - hand side: In $2CO_{2}$, O atoms is $2\times2=4$.

For $CO(g)+O_{2}(g)\to CO_{2}(g)$:
- **Oxygen (O)**:
  - Left - hand side: In $CO$, O atoms is $1$, from $O_{2}$ is $2$, total $1+2 = 3$.
  - Right - hand side: In $CO_{2}$, O atoms is $2$.

For $CO(g)+2O_{2}(g)\to2CO_{2}(g)$:
- **Carbon (C)**:
  - Left - hand side: In $CO$, C atoms is $1$.
  - Right - hand side: In $2CO_{2}$, C atoms is $2$.

## Step2: Apply the law of conservation of mass for Question 3
The law of conservation of mass states that mass is neither created nor destroyed in a chemical reaction.
The initial mass of the reactants is $m_{initial}=30g$ (antacid tablet) $+ 50g$ (water)$=80g$.
After the reaction, let the mass of gas be $m_{gas}$ and mass of liquid is $m_{liquid} = 50g$.
By the law of conservation of mass $m_{initial}=m_{gas}+m_{liquid}$.
So $m_{gas}=m_{initial}-m_{liquid}$.
Substitute $m_{initial} = 80g$ and $m_{liquid}=50g$, we get $m_{gas}=80 - 50=30g$.

# Answer:
Question 2: $2CO(g)+O_{2}(g)\to2CO_{2}(g)$
Question 3: $30$ grams

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QUESTION IMAGE

Question

Explanation:

Step1: Check the number of atoms for each element in the chemical equation

Step2: Apply the law of conservation of mass for Question 3

Answer: