question
in $ \triangle n o p $, $ m \angle n = 101 ^ { \circ } $ and $ m \angle o = 10 ^ { \circ } $. which statement about the sides of $ \triangle n o p $ must be
answer
true?
$ o p p n n o $
$ o p n o p n $
$ n o p n o p $
$ n o o p p n $
$ p n o p n o $
$ p n n o o p $

Question

question
in $ \triangle n o p $, $ m \angle n = 101 ^ { \circ } $ and $ m \angle o = 10 ^ { \circ } $. which statement about the sides of $ \triangle n o p $ must be
answer
true?
$ o p > p n > n o $
$ o p > n o > p n $
$ n o > p n > o p $
$ n o > o p > p n $
$ p n > o p > n o $
$ p n > n o > o p $

Accepted Answer

# Explanation:
## Step1: Find the measure of the third angle
In a triangle, the sum of angles is $180^{\circ}$. Given $m\angle N = 101^{\circ}$ and $m\angle O=10^{\circ}$, then $m\angle P=180-(101 + 10)=69^{\circ}$.
## Step2: Apply the triangle - side relationship (larger angle - larger side)
In $\triangle NOP$, the side opposite $\angle N$ is $OP$, the side opposite $\angle O$ is $PN$, and the side opposite $\angle P$ is $NO$. Since $101^{\circ}>69^{\circ}>10^{\circ}$, then $OP>NO>PN$ (because in a triangle, the larger the angle, the longer the side opposite it).

# Answer:
OP > NO > PN

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QUESTION IMAGE

Question

Explanation:

Step1: Find the measure of the third angle

Step2: Apply the triangle - side relationship (larger angle - larger side)

Answer: