Question

question 6 of 7
which of the following matrices is equal to $5\

$$\begin{bmatrix}-4&2\\\\0&-5\\end{bmatrix}$$

$?
$\bigcirc\

$$\begin{bmatrix}-20&-15\\end{bmatrix}$$

$
$\bigcirc\

$$\begin{bmatrix}-10\\\\-25\\end{bmatrix}$$

$
$\bigcirc\

$$\begin{bmatrix}1&7\\\\5&0\\end{bmatrix}$$

$
$\bigcirc\

$$\begin{bmatrix}-20&10\\\\0&-25\\end{bmatrix}$$

$

Explanation:

Step1: Recall scalar multiplication of matrices

To multiply a scalar (5) by a matrix, we multiply each element of the matrix by the scalar. The given matrix is

$$\begin{bmatrix} -4 & 2 \\ 0 & -5 \end{bmatrix}$$

.

Step2: Multiply each element by 5

• For the element in the first row, first column: $5\times(-4) = -20$
• For the element in the first row, second column: $5\times2 = 10$
• For the element in the second row, first column: $5\times0 = 0$
• For the element in the second row, second column: $5\times(-5) = -25$

So the resulting matrix is

$$\begin{bmatrix} -20 & 10 \\ 0 & -25 \end{bmatrix}$$

.

Answer:

$$\begin{bmatrix} -20 & 10 \\ 0 & -25 \end{bmatrix}$$

(the last option among the given choices)