Question

question
the triangle below is equilateral. find the length of side ( x ) to the nearest tenth.
( sqrt{5} )

Explanation:

Step1: Recall properties of equilateral triangles

In an equilateral triangle, the altitude (height) splits the triangle into two 30 - 60 - 90 right triangles and also bisects the base. Let the side length of the equilateral triangle be \( s=\sqrt{5} \). The altitude \( x \) of an equilateral triangle with side length \( s \) can be found using the formula for the height of an equilateral triangle: \( h = \frac{\sqrt{3}}{2}s \).

Step2: Substitute the side length into the formula

We know that \( s = \sqrt{5} \), so substitute \( s=\sqrt{5} \) into the formula \( h=\frac{\sqrt{3}}{2}s \).

$$
LATEXBLOCK0
$$

Answer:

\( 1.9 \)