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Question
question
put the following equation of a line into slope-intercept form, simplifying all fractions.
9x + 12y = -108
Step1: Isolate the y-term
Subtract \(9x\) from both sides of the equation \(9x + 12y=-108\).
We get \(12y=-9x - 108\).
Step2: Solve for y
Divide every term by 12 to solve for \(y\).
\(y=\frac{-9x}{12}-\frac{108}{12}\)
Simplify the fractions: \(\frac{-9}{12}=-\frac{3}{4}\) and \(\frac{-108}{12}=-9\).
So \(y = -\frac{3}{4}x-9\).
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\(y = -\frac{3}{4}x - 9\)