Question

question 3 1 pts which statement regarding balanced chemical equations is not true? coefficients are used in front of formulas to balance the equation. reactants are written to the left of the arrow. when no coefficient is written in front of a formula, the number one is assumed. the number of each kind of atoms must be the same on each side. subscripts may be changed to make an equation simpler to balance. question 4 1 pts when the reaction shown is correctly balanced, the coefficients are: kclo₃ → kcl + o₂ 2, 2, 1 2, 2, 3 1, 1, 1 2, 2, 2

Explanation:

Question 3

• In a balanced chemical equation, coefficients are used to balance the equation (so the first option is true). Reactants are on the left - hand side (LHS) of the arrow (second option is true). When no coefficient is written, it is assumed to be 1 (third option is true). The law of conservation of mass requires that the number of each kind of atom is the same on both sides (fourth option is true).
• Subscripts cannot be changed when balancing a chemical equation. Changing subscripts would change the identity of the substance. For example, in \(H_2O\), changing the subscript of \(H\) from 2 to 1 would change water to \(HO\), which is not a real substance.

Answer:

The statement “Subscripts may be changed to make an equation simpler to balance” is not true.

Question 4

Step1: Balance the oxygen atoms

The un - balanced equation is \(KClO_3
ightarrow KCl + O_2\).
Let the balanced equation be \(aKClO_3=bKCl + cO_2\).
For oxygen atoms: \(3a = 2c\). Let's find the least common multiple of 3 and 2. The LCM of 3 and 2 is 6.
If \(3a=6\), then \(a = 2\). If \(2c=6\), then \(c = 3\).

Step2: Balance the potassium and chlorine atoms

Substitute \(a = 2\) into the equation.
The left - hand side has \(2K\) and \(2Cl\) from \(2KClO_3\).
For the right - hand side, if \(b = 2\) (from \(bKCl\)), then the potassium (\(K\)) and chlorine (\(Cl\)) atoms are balanced (\(2K\) and \(2Cl\) on both sides).

The balanced equation is \(2KClO_3=2KCl + 3O_2\)