Question

question 1
3 pts
simplify:
$(-4x - 4y)(-6x - 6y)$
solution $= ax^2 + bxy + cy^2$
$= \square x^2 + \square xy + \square y^2$

Explanation:

Step1: Factor out common terms

First, factor out -4 from the first binomial and -6 from the second binomial:
\((-4x - 4y) = -4(x + y)\) and \((-6x - 6y) = -6(x + y)\).
Multiply the factored forms: \((-4)(-6)(x + y)(x + y) = 24(x + y)^2\).

Step2: Expand \((x + y)^2\)

Recall the formula \((a + b)^2 = a^2 + 2ab + b^2\). For \((x + y)^2\), this gives \(x^2 + 2xy + y^2\).

Step3: Multiply by 24

Multiply each term in \(x^2 + 2xy + y^2\) by 24:
\(24 \cdot x^2 + 24 \cdot 2xy + 24 \cdot y^2 = 24x^2 + 48xy + 24y^2\).

Answer:

\(24\) \(x^2 +\) \(48\) \(xy +\) \(24\) \(y^2\)