Question

question 1 - 1
ps lies on the perpendicular bisector of qr. what is the value of n?
q 6n + 3 s 4n + 11 r

Explanation:

Step1: Use the property of perpendicular bisector

Since \(PS\) is the perpendicular bisector of \(QR\), then \(QS = SR\).
So, \(6n + 3=4n + 11\).

Step2: Solve the equation for \(n\)

Subtract \(4n\) from both sides: \(6n-4n + 3=4n-4n + 11\), which gives \(2n+3 = 11\).
Subtract \(3\) from both sides: \(2n+3 - 3=11 - 3\), so \(2n=8\).
Divide both sides by \(2\): \(n=\frac{8}{2}\).

Answer:

\(n = 4\)