Question

question 1 (2 points)
how many moles of solute in 2.00 l of a 3.00 m solution?
the solute could be anything, and the solvent is usually water.
the concentration will always be the conversion factor. m stands for mol/l.
1 mol
(2 l)(---------) = 3 mol
4 l
a. 0 b. 1 c. 2 d. 3 e. 4 f. 5
g. 6 h. 234 i. 58.44 j. 100. k. 1.71
l. 0.856 m. 10.0

Explanation:

Step1: Recall the formula for molarity

Molarity ($M$) is defined as $M=\frac{n}{V}$, where $n$ is the number of moles of solute and $V$ is the volume of the solution in liters. Rearranging for $n$ gives $n = M\times V$.

Step2: Substitute the given values

Given $M = 3.00\ mol/L$ and $V=2.00\ L$. Then $n=(3.00\ mol/L)\times(2.00\ L)$.

Step3: Calculate the number of moles

$n = 3\times2=6\ mol$.

Looking at the blanks:

• For blank 1: The numerator in the formula (from $n = M\times V=\frac{mol}{L}\times L$) is the number of moles. Here, when using the unit - conversion approach ($n = V\times\frac{mol}{L}$), the value in the numerator (blank 1) is the molarity value in terms of moles. So blank 1 is $3.00$ (but looking at the options, if we consider the final calculation result for the moles of solute, and the structure of the problem as a unit - conversion ($n = V\times\frac{mol}{L}$)), in the context of the problem's setup (where they are using $n=V\times\frac{mol}{L}$), the number of moles (blank 3) is $6$. And since $M = 3\ mol/L$, blank 1 is $3$, blank 2 is $2.00$, blank 4 is $1.00$ (because $M=\frac{mol}{L}$ implies $\frac{3\ mol}{1\ L}$).

Answer:

1. D. 3
2. C. 2
3. G. 6
4. B. 1