Question

question 4 (3 points)
answer the questions about the balanced reaction 3a + 2b → 1c + 100. cal
how many moles of a are required to make 100. cal? 1
how many moles of a are required to make 200. cal? 2
is the relationship between moles of a and cal a direct proportion? 3
a. 0 b. 1 c. 2 d. 3 e. 4 f. 5 g. 6 h. 7
i. yes j. no

Explanation:

Step1: Analyze the reaction equation

From the balanced reaction \(3A + 2B
ightarrow1C + 100\space cal\), we can see that when \(3\) moles of \(A\) react, \(100\space cal\) of energy is produced.

Step2: Calculate moles of \(A\) for \(200\space cal\)

Since the energy and moles of \(A\) are in proportion. If \(3\) moles of \(A\) give \(100\space cal\), for \(200\space cal\) (which is \(2\times100\space cal\)), the moles of \(A\) required is \(2\times3 = 6\) moles.

Step3: Check the proportion relationship

Let \(y\) be the moles of \(A\) and \(x\) be the energy in cal. We have the relationship \(y=\frac{3}{100}x\). This is of the form \(y = kx\) (\(k=\frac{3}{100}\), a constant), so it is a direct proportion.

Answer:

1. D. 3
2. G. 6
3. I. yes