Question

question 7 (1 point)
write the chemical formula for each ionic compound
mercury (ii) chloride

question 8 (1 point)
write the chemical formula for each ionic compound
copper (ii) selenide

Explanation:

Step1: Determine the ions

• Mercury (II) has a charge of \(Hg^{2+}\). Chloride ion is \(Cl^{-}\).
• Copper (II) has a charge of \(Cu^{2+}\). Selenide ion is \(Se^{2 -}\).

Step2: Balance the charges

• For mercury (II) chloride: To balance the +2 charge of \(Hg^{2+}\), we need 2 \(Cl^{-}\) ions. So the formula is \(HgCl_{2}\).
• For copper (II) selenide: The +2 charge of \(Cu^{2+}\) and - 2 charge of \(Se^{2 -}\) balance each other. So the formula is \(CuSe\).

Answer:

Question 7: \(HgCl_{2}\)
Question 8: \(CuSe\)