Question

question 5 (1 point)
which of the following molecules demonstrates a trigonal planar molecular shape?
no3
sf3
bf3
h3o+

Explanation:

• For \(NO_3\), it should be \(NO_3^-\). The central \(N\) atom has 3 bonding pairs and 0 lone pairs. Using VSEPR theory, it has a trigonal - planar shape.
• For \(SF_3\), it should be \(SF_3^+\). The central \(S\) atom has 3 bonding pairs and 1 lone pair. According to VSEPR theory, it has a trigonal - pyramidal shape.
• For \(BF_3\), the central \(B\) atom has 3 bonding pairs and 0 lone pairs. By VSEPR theory, it has a trigonal - planar shape.
• For \(H_3O^+\), the central \(O\) atom has 3 bonding pairs and 1 lone pair. Based on VSEPR theory, it has a trigonal - pyramidal shape.

Answer:

\(BF_3\) and \(NO_3^-\) (assuming the question had a typo for \(NO_3\) as \(NO_3^-\)). If we consider the options as given (assuming \(NO_3\) is a typo and we go with the available correctly - named \(BF_3\) in the options), the answer is \(BF_3\).