Question

question 1 (1 point)
which of the following elements is the most electronegative?
o
n
s
p
question 2 (1 point)
electronegativity is used to
determine if a bond is ionic
determine if a bond is covalent
determine the extent of electron sharing in a bond
determine polarity of a bond
all of the above

Explanation:

Question 1

Electronegativity increases across a period (from left to right) and decreases down a group in the periodic table. Among the given elements, \(O\) (oxygen) is to the right of \(N\) (nitrogen) in the same period. \(S\) (sulfur) and \(P\) (phosphorus) are in lower periods than \(O\) and \(N\). So, \(O\) has the highest electronegativity.

• For ionic bonds: If the electronegativity difference (\(\Delta EN\)) between two atoms is \(\Delta EN> 1.7\), the bond is considered ionic.
• For covalent bonds: If \(\Delta EN < 1.7\), the bond is covalent.
• The extent of electron - sharing: A higher electronegativity difference means less equal electron - sharing.
• Polarity of a bond: A non - zero electronegativity difference makes the bond polar. Since all these aspects (ionic/covalent nature, electron - sharing extent, bond polarity) are determined using electronegativity values.

Answer:

O

Question 2