Question

question 3 (1 point)
which of the following is the correct name for the structure below?
trans - non - 4 - yne
cis - non - 5 - ene
trans - non - 4 - ene
cis - non - 4 - ene
question 4 (1 point)
what is the shape of an alkyne molecule?
bent
linear
tetrahedral
trigonal planar
cyclic

Explanation:

Question 3

• The compound is an alkene (ends with -ene), not an alkyne (-yne), so "trans - non - 4 - yne" is incorrect.
• For naming alkenes, we number the carbon chain to give the double bond the lowest number. Here, the double bond is at the 4th carbon (non - 4 - ene).
• In the structure, the two groups attached to the double - bonded carbons are on opposite sides (trans configuration). "cis - non - 5 - ene" has incorrect numbering and configuration. "cis - non - 4 - ene" has incorrect configuration.

• Alkynes have a triple bond (\(C\equiv C\)). The carbon atoms involved in the triple bond are \(sp\) hybridized.
• \(sp\) hybridized carbon atoms have a linear geometry (bond angle \(180^{\circ}\)).
• Bent shape is often seen in molecules like \(H_2O\) ( \(sp^3\) hybridized with lone pairs). Tetrahedral is for \(sp^3\) hybridized atoms with four bonding groups (e.g., \(CH_4\)). Trigonal planar is for \(sp^2\) hybridized atoms (e.g., \(BF_3\)). Cyclic refers to ring - shaped molecules, which is not a general shape for alkynes.

Answer:

trans - non - 4 - ene

Question 4