Question

question 1 · 1 point
what is the molarity of cacl₂ when 1.92 mol of cacl₂ is dissolved in water to form 515 ml of solution?
select the correct answer below:
3.73 m
0.268 m
3.73 × 10⁻³ m
0.989 m

Explanation:

Step1: Convert volume to liters

The formula for molarity \(M=\frac{n}{V}\) (where \(n\) is the number of moles and \(V\) is the volume of the solution in liters). Given \(V = 515\ mL\). Since \(1\ L=1000\ mL\), then \(V=\frac{515}{1000}\ L = 0.515\ L\).

Step2: Calculate molarity

We know \(n = 1.92\ mol\) and \(V=0.515\ L\). Substitute into the molarity formula: \(M=\frac{1.92\ mol}{0.515\ L}\approx3.73\ M\)

Answer:

A. \(3.73\ M\)