Question

question 2 · 1 point
a sample of a gas has a pressure of 248 mm hg when the volume is 1.05 l. what is the pressure of the gas when the volume is 3.98 l?
select the correct answer below:
940 mm hg
65.4 mm hg
0.0153 mm hg
81.6 mm hg

Explanation:

Step1: Recall Boyle's Law

Boyle's Law is \(P_1V_1 = P_2V_2\), where \(P_1\) and \(V_1\) are the initial pressure and volume, and \(P_2\) and \(V_2\) are the final pressure and volume.

Step2: Substitute the given values

Given \(P_1=248\ \text{mm Hg}\), \(V_1 = 1.05\ \text{L}\), and \(V_2=3.98\ \text{L}\). We need to find \(P_2\).
From \(P_1V_1 = P_2V_2\), we can solve for \(P_2\) as \(P_2=\frac{P_1V_1}{V_2}\).
Substitute the values: \(P_2=\frac{248\times1.05}{3.98}\).

Step3: Calculate \(P_2\)

First, calculate \(248\times1.05 = 260.4\).
Then, \(P_2=\frac{260.4}{3.98}\approx65.4\ \text{mm Hg}\).

Answer:

B. \(65.4\ \text{mm Hg}\)