Question

question 9 (1 point)
an overlay of an accessibility ramp of a building is placed on the standard (x,y) coordinate plane so that the x-axis aligns with the horizontal. the line segment representing the side view of the ramp goes through the points (-2,-1) and (16,2). what is the slope of the accessibility ramp?
f. -3
g. $-\dfrac{1}{3}$
h. $-\dfrac{1}{6}$
j. $\dfrac{1}{6}$
k. $\dfrac{1}{14}$
\bigcirc a \quad f
\bigcirc b \quad j
\bigcirc c \quad g
\bigcirc d \quad h
\bigcirc e \quad k

Explanation:

Step1: Recall slope formula

The slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \( m=\frac{y_2 - y_1}{x_2 - x_1} \).

Step2: Identify points

Let \((x_1, y_1)=(-2, -1)\) and \((x_2, y_2)=(16, 2)\).

Step3: Substitute into formula

Substitute the values into the slope formula: \( m=\frac{2 - (-1)}{16 - (-2)}=\frac{2 + 1}{16 + 2}=\frac{3}{18}=\frac{1}{6} \).

Answer:

J. \(\frac{1}{6}\)