Question

question 2 (1 point)
how many moles of nbr₃ can be made from 2.22 x 10² moles of n₂? (answer = 4.44 x 10² mol nbr₃)
n₂ + 3 br₂ → 2 nbr₃ + 44.0 kj
(2.22 x 10² mol n₂)(-----) = _2_ mol nbr₃
a. 1 b. 2 c. 3 d. 4 e. 5 f. 253.719 g. 3.38 x 10⁰
h. 3.26 x 10³ i. 44.0 j. 1.33 x 10⁻² k. 9.77 x 10³ l. 4.44 x 10²
m. 6.66 x 10² n. 500.0 o. 556 p. 90.0 q. 3.2852 r. 159.81
s. 28.013 t. 1.750 u. 0.8750 v. 13.0 w. 0.46306 x. 1.3892
y. 24.5 z. 38.5 aa. 2.190 bb. 250.

Explanation:

Step1: Determine mole ratio

From the balanced equation \(N_2 + 3Br_2
ightarrow2NBr_3\), the mole ratio of \(NBr_3\) to \(N_2\) is \(2:1\). So the value for blank 1 is \(2\) (moles of \(NBr_3\)) and for blank 3 is \(1\) (mole of \(N_2\)).

Step2: Calculate moles of \(NBr_3\)

Using the formula \((2.22\times 10^{2}\text{ mol }N_2)\times\frac{2\text{ mol }NBr_3}{1\text{ mol }N_2}\).

$$
LATEXBLOCK0
$$

So the value for blank 2 is \(4.44\times 10^{2}\) (moles of \(NBr_3\)).

Answer:

1. B. 2
2. L. \(4.44\times 10^{2}\)
3. A. 1