question 3

jill mixes two types of concentrations of hcl (hydrochloric acid):
0.375 liters of 25% hydrochloric acid and 0.625 liters of 65%
hydrochloric acid.

what is the hcl concentration of the mixed solution?

40%
50%
56%
44%

Question

question 3

jill mixes two types of concentrations of hcl (hydrochloric acid):
0.375 liters of 25% hydrochloric acid and 0.625 liters of 65%
hydrochloric acid.

what is the hcl concentration of the mixed solution?

40%
50%
56%
44%

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Mixture Problems", "Weighted Average Concentration" ], "new_concepts": [], "current_concepts": [ "Mixture Problems", "Weighted Average Concentration" ] } ## Calculate the total amount of pure HCl Using the *Mixture Problems* and *Weighted Average Concentration* knowledge points $$ \begin{aligned} \text{Pure HCl from first solution} &= 0.375 \times 0.25 = 0.09375\text{ liters} \ \text{Pure HCl from second solution} &= 0.625 \times 0.65 = 0.40625\text{ liters} \ \text{Total pure HCl} &= 0.09375 + 0.40625 = 0.5\text{ liters} \end{aligned} $$ ## Calculate the total volume of the mixed solution Using the *Mixture Problems* knowledge point $$ \text{Total Volume} = 0.375 + 0.625 = 1.0\text{ liter} $$ ## Determine the concentration of the mixture Using the *Weighted Average Concentration* knowledge point $$ \begin{aligned} \text{Concentration} &= \frac{\text{Total pure HCl}}{\text{Total Volume}} \ &= \frac{0.5}{1.0} = 0.5 = 50\% \end{aligned} $$

40%

50%

56%

44%

{ "subject": "Mathematics", "question_type": "Multiple Choice", "knowledge_point": [ "Mathematics", "Algebra", "Mixture Problems" ] }

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QUESTION IMAGE

Question

Explanation:

Calculate the total amount of pure HCl

Calculate the total volume of the mixed solution

Determine the concentration of the mixture

Answer: