Question

question: the image point of a after a translation right 3 units and up 3 units is the point b(0, 6). determine the coordinates of the pre - image point a.

Explanation:

Step1: Recall translation rule

For a translation right $h$ units and up $k$ units, the rule is $(x,y)\to(x + h,y + k)$. Here $h = 3,k = 3$. Let the pre - image point $A$ be $(x,y)$ and the image point $B=(0,6)$.

Step2: Set up equations

We have $x+3 = 0$ and $y + 3=6$.

Step3: Solve for $x$

From $x+3 = 0$, we get $x=0 - 3=-3$.

Step4: Solve for $y$

From $y + 3=6$, we get $y=6 - 3 = 3$. So the pre - image point $A$ is $(-3,3)$.

Answer:

$(- 3,3)$