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question 2 given wxyz is a parallelogram, what is the measure of ∠z? im…

Question

question 2
given wxyz is a parallelogram, what is the measure of ∠z?
image of parallelogram wxyz with ∠x = 35°
options: 25°, 35°, 55°, 145°

Explanation:

Step1: Recall parallelogram angle property

In a parallelogram, consecutive angles are supplementary (sum to \(180^\circ\)), and opposite angles are equal. Also, \(XY \parallel WZ\) and \(XW \parallel YZ\), so \(\angle X\) and \(\angle Z\) are consecutive angles? Wait, no—wait, in parallelogram \(WXYZ\), sides \(XW\) and \(YZ\) are parallel, and \(XY\) and \(WZ\) are parallel. So \(\angle X\) and \(\angle Z\): Wait, actually, in a parallelogram, consecutive angles (adjacent angles) are supplementary, and opposite angles are equal. Wait, let's label the parallelogram: vertices \(W, X, Y, Z\) in order, so sides \(WX\) and \(YZ\) are parallel, \(XY\) and \(WZ\) are parallel. So \(\angle X\) (at vertex \(X\)) and \(\angle Z\) (at vertex \(Z\)): Wait, no, \(\angle X\) and \(\angle W\) are consecutive, \(\angle X\) and \(\angle Y\) are consecutive? Wait, maybe I mixed up. Wait, in a parallelogram, opposite angles are equal. So \(\angle X = \angle Z\)? Wait, no, wait: let's check the sides. \(X\) is connected to \(Y\) and \(W\), \(Z\) is connected to \(Y\) and \(W\). So \(XY \parallel WZ\), and \(XW \parallel YZ\). So the angle at \(X\) (\(\angle X\)) and angle at \(Z\) (\(\angle Z\)): are they consecutive or opposite? Wait, in parallelogram \(WXYZ\), the vertices are in order, so the angles are \(\angle W\), \(\angle X\), \(\angle Y\), \(\angle Z\), with \(\angle W\) opposite \(\angle Y\), and \(\angle X\) opposite \(\angle Z\)? Wait, no, that's not right. Wait, in a parallelogram, opposite angles are equal. So if \(WXYZ\) is a parallelogram, then \(WX \parallel YZ\) and \(XY \parallel WZ\). So \(\angle X\) and \(\angle Z\): let's see, \(X\) is between \(W\) and \(Y\), \(Z\) is between \(Y\) and \(W\). So the sides \(XW\) and \(YZ\) are parallel, and \(XY\) and \(WZ\) are parallel. So the angle at \(X\) (between \(XW\) and \(XY\)) and the angle at \(Z\) (between \(YZ\) and \(WZ\)): since \(XW \parallel YZ\) and \(XY \parallel WZ\), the consecutive angles (like \(\angle X\) and \(\angle W\)) are supplementary, but \(\angle X\) and \(\angle Z\): wait, no, actually, in a parallelogram, consecutive angles (adjacent) are supplementary, and opposite angles are equal. Wait, maybe I made a mistake. Wait, let's take a standard parallelogram: \(ABCD\), with \(AB \parallel CD\) and \(AD \parallel BC\). Then \(\angle A = \angle C\), \(\angle B = \angle D\), and \(\angle A + \angle B = 180^\circ\), etc. So in our case, \(WXYZ\), so let's map to \(ABCD\): \(W \to A\), \(X \to B\), \(Y \to C\), \(Z \to D\). So \(\angle X\) (at \(X\)) is like \(\angle B\), \(\angle Z\) (at \(Z\)) is like \(\angle D\). Wait, no, \(Z\) would be \(D\), so \(\angle D\) is opposite \(\angle B\)? No, \(\angle A\) ( \(W\)) and \(\angle C\) ( \(Y\)) are opposite, \(\angle B\) ( \(X\)) and \(\angle D\) ( \(Z\)) are opposite? Wait, no, in \(ABCD\), \(\angle A\) (at \(A\)) and \(\angle C\) (at \(C\)) are opposite, \(\angle B\) (at \(B\)) and \(\angle D\) (at \(D\)) are opposite. So in \(WXYZ\), \(\angle W\) (at \(W\)) and \(\angle Y\) (at \(Y\)) are opposite, \(\angle X\) (at \(X\)) and \(\angle Z\) (at \(Z\)) are opposite? Wait, that can't be, because in the diagram, \(\angle X\) is \(35^\circ\), and the options include \(35^\circ\) and \(145^\circ\). Wait, maybe I got the consecutive angles wrong. Wait, in the diagram, the parallelogram is drawn with \(X\) connected to \(Y\) and \(W\), \(Y\) connected to \(X\) and \(Z\), \(Z\) connected to \(Y\) and \(W\), \(W\) connected to \(Z\) and \(X\). So the sides \(XY\) and \(WZ\) are parallel, \(XW\) and \(YZ\) are parallel. So \(\angle…

Answer:

\(35^\circ\) (the option with \(35^\circ\))