QUESTION IMAGE
Question
question
given: \\( \overline { d e } \cong \overline { c e } \\), \\( \overline { a d } \perp \overline { d b } \\) and \\( \overline { b c } \perp \overline { c a } \\).
prove: \\( \triangle a e b \\) is an isosceles triangle.
step
statement - reason
1
\\( \overline { d e } \cong \overline { c e } \\)
\\( \overline { a d } \perp \overline { d b } \\)
\\( \overline { b c } \perp \overline { c a } \\)
given
Step1: Prove \(\triangle ADE\cong\triangle BCE\)
Since \(\overline{AD}\perp\overline{DB}\) and \(\overline{BC}\perp\overline{CA}\), \(\angle ADE = \angle BCE=90^{\circ}\).
We know that \(\angle AED=\angle BEC\) (vertical angles are equal) and \(\overline{DE}\cong\overline{CE}\) (given).
By the Angle - Angle - Side (AAS) congruence criterion (\(\angle ADE=\angle BCE\), \(\angle AED = \angle BEC\), \(\overline{DE}=\overline{CE}\)), \(\triangle ADE\cong\triangle BCE\).
Step2: Find the relationship between \(AE\) and \(BE\)
Because \(\triangle ADE\cong\triangle BCE\), corresponding parts of congruent triangles are equal. So, \(\overline{AE}\cong\overline{BE}\).
Step3: Use the definition of an isosceles triangle
A triangle is isosceles if it has at least two congruent sides. Since \(\overline{AE}\cong\overline{BE}\) in \(\triangle AEB\), by the definition of an isosceles triangle, \(\triangle AEB\) is an isosceles triangle.
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\(\triangle AEB\) is an isosceles triangle.