Question

question
fully simplify using only positive exponents.
$(-2j^{10}k^{-2}l^{0})(5j^{-3}k^{-6})$

Explanation:

Step1: Simplify the constant terms

Multiply the numerical coefficients:
$(-2) \times 5 = -10$

Step2: Simplify $j$ terms

Add exponents of like bases:
$j^{10} \times j^{-3} = j^{10 + (-3)} = j^{7}$

Step3: Simplify $k$ terms

Add exponents of like bases:
$k^{-2} \times k^{-6} = k^{-2 + (-6)} = k^{-8}$
Rewrite with positive exponent: $k^{-8} = \frac{1}{k^{8}}$

Step4: Simplify $l$ term

Any non-zero term to the 0 power is 1:
$l^{0} = 1$

Step5: Combine all simplified terms

Multiply the results together:
$-10 \times j^{7} \times \frac{1}{k^{8}} \times 1$

Answer:

$\frac{-10j^{7}}{k^{8}}$