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question find the reference angle for a rotation of \\frac{10\\pi}{9}. …

Question

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find the reference angle for a rotation of \frac{10\pi}{9}.
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Explanation:

Step1: Determine the quadrant

Since \(\frac{10\pi}{9}\) is in the third quadrant (\(\pi<\frac{10\pi}{9}<\frac{3\pi}{2}\)).

Step2: Calculate the reference angle

The formula for the reference angle \(\theta_{ref}\) of an angle \(\theta\) in the third quadrant is \(\theta_{ref}=\theta - \pi\).
Substitute \(\theta=\frac{10\pi}{9}\) into the formula: \(\theta_{ref}=\frac{10\pi}{9}-\pi=\frac{10\pi - 9\pi}{9}=\frac{\pi}{9}\)

Answer:

\(\frac{\pi}{9}\)