Question

question
factor completely.
$36x^2 - 121$
answer attempt 1 out of 2

Explanation:

Step1: Identify the form

The expression \(36x^2 - 121\) is a difference of squares. The formula for factoring a difference of squares is \(a^2 - b^2=(a + b)(a - b)\).

Step2: Find \(a\) and \(b\)

For \(36x^2\), we can write it as \((6x)^2\), so \(a = 6x\). For \(121\), we can write it as \(11^2\), so \(b = 11\).

Step3: Apply the formula

Using the difference of squares formula, we substitute \(a = 6x\) and \(b = 11\) into \((a + b)(a - b)\). So \(36x^2 - 121=(6x + 11)(6x - 11)\).

Answer:

\((6x + 11)(6x - 11)\)