Question

question 5 5.6 class practice solve for x. solve for y.

Explanation:

Solve for \( x \)

Step1: Identify the triangle type

The triangle has a \( 60^\circ \) angle and the base is bisected (marked with a midpoint), and two sides (the left side is 230 m, and the triangle appears equilateral or isoceles with the vertex angle \( 60^\circ \)). In a triangle, if one angle is \( 60^\circ \) and it's isoceles (or with the midpoint), it's equilateral. So all angles are \( 60^\circ \). Thus, \( 15x = 60 \).

Step2: Solve for \( x \)

Divide both sides by 15: \( x=\frac{60}{15}=4 \).

Solve for \( y \)

Step1: Identify side lengths

Since the triangle is equilateral, all sides are equal. The left side is 230 m, so the right side \( 12y + 8 = 230 \).

Step2: Solve for \( y \)

Subtract 8: \( 12y = 230 - 8 = 222 \). Divide by 12: \( y=\frac{222}{12}=18.5 \).

Answer:

For \( x \): \( \boldsymbol{4} \)
For \( y \): \( \boldsymbol{18.5} \)