Question

question
a certain television is advertised as a 59 - inch tv (the diagonal length). if the width of the tv is
49 inches, how tall is the tv? round to the nearest tenth of an inch.

Explanation:

Step1: Apply Pythagorean theorem

Let the height be \(h\). By Pythagorean theorem \(h^{2}+49^{2}=59^{2}\), so \(h^{2}=59^{2}-49^{2}\).

Step2: Calculate \(h^{2}\)

\(h^{2}=(59 + 49)(59 - 49)\) (using \(a^{2}-b^{2}=(a + b)(a - b)\)). \(h^{2}=(108)(10)=1080\).

Step3: Find \(h\)

\(h=\sqrt{1080}\approx32.9\)

Answer:

\(32.9\) inches