Question

question 26 of 28 a ball is thrown up into the air. when it falls back down and reaches the ground, its final downward velocity is 8.0 m/s. what was the maximum height of the ball? (hint: keinitial = 0, pefinal = 0.) a. 3.3 m b. 32 m c. 6.5 m d. 0.41

Explanation:

Step1: Apply energy conservation

$mgh = \frac{1}{2}mv^2$

Step2: Solve for height h

$h = \frac{v^2}{2g}$

Step3: Substitute values (v=8m/s, g=9.8m/s²)

$h = \frac{8^2}{2\times9.8} \approx 3.3\ \text{m}$

Answer:

A. 3.3 m