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Question
question 24 of 29
is the following reaction balanced? (6.8 points)
extra content
co₂ + 6h₂o → c₆h₁₂o₆ + 6o₂
a. yes
b. no
question 25 of 29
how many atoms of carbon? (1.4 points)
extra content
3nahco₃
a. 3
b. 6
c. 9
d. 12
Step1: Count atoms on reactant side
For \(CO_2\), carbon atoms: \(1\) (from \(CO_2\)), and there is no coefficient for \(CO_2\) in the given reaction. For \(H_2O\), no carbon. Total carbon on reactant side: \(1\). Hydrogen atoms: \(2\times6 = 12\) (from \(6H_2O\)). Oxygen atoms: \(2\times1+ 1\times6=8\) ( \(2\) from each \(CO_2\) molecule and \(1\) from each \(H_2O\) molecule).
Step2: Count atoms on product side
For \(C_6H_{12}O_6\), carbon atoms: \(6\), hydrogen atoms: \(12\), oxygen atoms: \(6\). For \(6O_2\), oxygen atoms: \(2\times6 = 12\). Total oxygen on product side: \(6 + 12=18\), carbon: \(6\), hydrogen: \(12\). Since carbon atoms are not balanced ( \(1\) vs \(6\) on reactant and product side respectively), the reaction \(CO_2+6H_2O
ightarrow C_6H_{12}O_6 + 6O_2\) is not balanced.
For \(3NaHCO_3\), the sub - script of \(C\) is \(1\) and the coefficient is \(3\). Using the formula \(n=\text{coefficient}\times\text{sub - script}\), the number of \(C\) atoms \(n = 3\times1=3\)
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Question 24: B. No
Question 25: A. 3