Question

question 21
what volume of a 1.544 m solution contains 106.5 g of sodium sulfate, na2so4? (mm = 142.04 g mol-1)
o 0.007042 l
o 2.059 l
o 0.4858 l
o 14.50 l

Explanation:

Step1: Calculate moles of \(Na_2SO_4\)

Use the formula \(n=\frac{m}{M}\), where \(m = 106.5\space g\) (mass of \(Na_2SO_4\)) and \(M=142.04\space g/mol\) (molar mass of \(Na_2SO_4\)).
\(n=\frac{106.5\space g}{142.04\space g/mol}\approx0.75\space mol\)

Step2: Calculate volume of the solution

Use the formula \(V=\frac{n}{C}\), where \(n = 0.75\space mol\) (moles of \(Na_2SO_4\)) and \(C = 1.544\space M\) (molarity of the solution).
\(V=\frac{0.75\space mol}{1.544\space mol/L}\approx0.4858\space L\)

Answer:

0.4858 L