Question

question 21 (4 points)
which of the following substances is more likely to dissolve in ccl₄?
a) ch₃ch₂oh
b) cbr₄
c) hbr
d) hcl

Explanation:

To determine which substance dissolves in \( \text{CCl}_4 \) (a non - polar solvent), we use the "like dissolves like" principle. Non - polar substances dissolve in non - polar solvents, and polar substances dissolve in polar solvents.

• Option a: \( \text{CH}_3\text{CH}_2\text{OH} \) (ethanol) has a polar \( -\text{OH} \) group, so it is a polar molecule.
• Option b: \( \text{CBr}_4 \) (carbon tetrabromide) is a non - polar molecule. The four \( \text{Br} \) atoms are symmetrically arranged around the \( \text{C} \) atom, so the dipole moments cancel out.
• Option c: \( \text{HBr} \) (hydrogen bromide) is a polar molecule because of the electronegativity difference between \( \text{H} \) and \( \text{Br} \).
• Option d: \( \text{HCl} \) (hydrogen chloride) is a polar molecule due to the electronegativity difference between \( \text{H} \) and \( \text{Cl} \).

Since \( \text{CCl}_4 \) is non - polar, the non - polar substance \( \text{CBr}_4 \) will dissolve in it.

Answer:

b) \( \text{CBr}_4 \)