Question

question 204 the nature of electricity
what is the potential at a distance of 5 m from a particle that has a charge of 5 nc in the air?
select one
4.5 v
25 v
2.5 v
5 v
9 v

Explanation:

Step1: Recall the formula for electric potential

The formula for electric potential \( V\) due to a point - charge \( q\) at a distance \( r\) is \( V=\frac{kq}{r}\), where \( k = 9\times10^{9}\ N\cdot m^{2}/C^{2}\)

Step2: Convert the charge unit

Given \( q = 5\ nC=5\times10^{-9}\ C\) and \( r = 5\ m\)

Step3: Substitute the values into the formula

Substitute \( k = 9\times10^{9}\ N\cdot m^{2}/C^{2}\), \( q = 5\times10^{-9}\ C\) and \( r = 5\ m\) into \( V=\frac{kq}{r}\)

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Answer:

9V