Question

question 5

1. how many atoms are found in 999 moles of neon?

x 10 atoms ne

Explanation:

Step1: Recall Avogadro's number

Avogadro's number \( N_A=6.022\times 10^{23}\text{ atoms/mol}\).

Step2: Use the formula \(N = n\times N_A\)

Given \(n = 999\space mol\) of \(Ne\). Then \(N=999\times6.022\times 10^{23}\) atoms.

$$N=(1000 - 1)\times6.022\times 10^{23}=(1000\times6.022\times 10^{23})-(1\times6.022\times 10^{23})$$

$$N = 6.022\times 10^{26}-6.022\times 10^{23}$$

$$N=6.015978\times 10^{26}\text{ atoms}$$

Answer:

\(6.02\times 10^{26}\) atoms \(Ne\) (rounded to three significant figures)