Question

question 15 of 25 if \\(\angle avb\\) has a measure of 70° and \\(\overrightarrow{vm}\\) is its angle bisector, what is the measure of \\(\angle avm\\)?

Explanation:

Step1: Recall angle - bisector property

An angle bisector divides an angle into two equal parts.

Step2: Calculate the measure of ∠AVM

If ∠AVB = 70° and VM is the angle - bisector of ∠AVB, then ∠AVM=$\frac{1}{2}$∠AVB. So, ∠AVM = $\frac{70^{\circ}}{2}=35^{\circ}$.

Answer:

A. 35°