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question 13 of 25
the side lengths of a 45 - 45 - 90 triangle are in the ratio ( 1:1:sqrt{2} ). what is ( sin 45^{circ} )?
a. ( \frac{sqrt{2}}{2} )
b. ( \frac{1}{2} )
c. 1
d. ( sqrt{2} )
Step1: Recall sine definition
$\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}$
Step2: Assign sides to 45-45-90 triangle
Let legs = 1, hypotenuse = $\sqrt{2}$
Step3: Calculate $\sin45^\circ$
$\sin45^\circ = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}$
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A. $\frac{\sqrt{2}}{2}$