Question

question 2
a 12 - kg crate is pushed up an incline from point a to point b as shown in the figure. what is the change in the gravitational potential energy (δpe = pef - peo) of the crate?
+590 j
-590 j
this cannot be determined without knowing the angle of the incline.
+1200 j
-1200 j

Explanation:

Step1: Determine the height difference

The height difference \(\Delta h\) between point \(B\) and point \(A\) is \(h_{B}-h_{A}=7.0 - 2.0=5.0\space m\)

Step2: Use the formula for gravitational potential energy change

The formula for the change in gravitational potential energy is \(\Delta PE =mg\Delta h\), where \(m = 12\space kg\), \(g = 9.8\space m/s^{2}\), and \(\Delta h=5.0\space m\)

$$
LATEXBLOCK0
$$

Since the crate is moved to a higher position, \(\Delta PE>0\)

Answer:

+590 J