Question

question 11 (3 points) fill in all of the missing information; 1 symbol and 3 numbers (from the letter choices below) a 4 7 b + he → li c 2 d a = 1 b = 2 c = 3 d = 4 a. -1 b. 0 c. 1 d. 2 e. 3 f. 4 g. 5 h. 6 i. 7 j. 8 k. 9 l. 10 m. 11 n. beta o. gamma p. alpha q. h r. be s. b t. c

Explanation:

Step1: Balance mass - number

In a nuclear reaction, the sum of mass - numbers on the left - hand side equals the sum of mass - numbers on the right - hand side. The mass - number of He is 4 and the mass - number of Li is 7. Let the mass - number of B be $A$. Then $A + 4=7$, so $A = 3$.

Step2: Balance atomic - number

The atomic - number of He is 2 and assume the atomic - number of B is $C$. The atomic - number of Li is 3. Then $C + 2=3$, so $C = 1$.

Step3: Identify the element

The element with atomic - number 1 is hydrogen ($H$).

Step4: Determine the remaining number

Since the reaction is balanced in terms of mass - number and atomic - number, and we have found the other values, for the mass - number of $H$ which we assumed as $A$ is 3, and for the atomic - number of $H$ which is $C$ is 1. Now, for the unknown $D$, in the context of this nuclear reaction balancing, considering the mass - number relationship, it is 3.

Answer:

1. E. 3
2. Q. H
3. C. 1
4. E. 3