Question

question 2 of 10
which polyhedron has more faces than a hexahedron but fewer faces than a dodecahedron?
a. tetrahedron
b. icosahedron
c. cube
d. octahedron

Explanation:

Step1: Recall the number of faces of each polyhedron

• A tetrahedron has \(4\) faces.
• An icosahedron has \(20\) faces.
• A cube (a type of hexahedron) has \(6\) faces.
• An octahedron has \(8\) faces.
• A dodecahedron has \(12\) faces.

Step2: Compare the number of faces

We need a polyhedron with more faces than a hexahedron (\(6\) faces) and fewer faces than a dodecahedron (\(12\) faces).

• For option A: \(4<6\), so tetrahedron is not correct.
• For option B: \(20 > 12\), so icosahedron is not correct.
• For option C: A cube is a hexahedron (\(6\) faces), so it is not correct.
• For option D: \(6<8<12\), so octahedron is correct.

Answer:

D. Octahedron