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Question
question 8 of 10
what is the solution to the equation below? round your answer to two decimal places.
\log_{5}(2x - 3) = 2
a. x = 11
b. x = \frac{29}{2}
c. x = 14
d. x = \frac{35}{2}
Step1: Convert log to exponential form
Using the definition of logarithms: if $\log_b(a) = c$, then $a = b^c$. So for $\log_5(2x - 3) = 2$, we get $2x - 3 = 5^2$.
Step2: Simplify the equation
Calculate $5^2 = 25$, so the equation becomes $2x - 3 = 25$.
Step3: Solve for x
Add 3 to both sides: $2x = 25 + 3 = 28$. Then divide by 2: $x = \frac{28}{2} = 14$.
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C. \( x = 14 \)