Question

question 7 of 10
what is the point - slope form of a line with slope - 3 that contains the point (10, -1)?
a. $y + 1 = -3(x - 10)$
b. $x + 1 = -3(y - 10)$
c. $y + 1 = 3(x + 10)$
d. $y + 1 = 3(x - 10)$

Explanation:

Step1: Recall point - slope formula

The point - slope form of a line is given by $y - y_1=m(x - x_1)$, where $m$ is the slope of the line and $(x_1,y_1)$ is a point on the line.

Step2: Identify values of \(m\), \(x_1\) and \(y_1\)

We are given that the slope \(m=- 3\) and the point \((x_1,y_1)=(10,-1)\).

Step3: Substitute values into the formula

Substitute \(m = - 3\), \(x_1=10\) and \(y_1=-1\) into the point - slope formula \(y - y_1=m(x - x_1)\).
We get \(y-(-1)=-3(x - 10)\), which simplifies to \(y + 1=-3(x - 10)\).

Answer:

A. \(y + 1=-3(x - 10)\)