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Question
question 3 of 10
what is the oxidation state of p in $po_4^{3-}$?
a. +2
b. +8
c. +5
d. +3
Step1: Set variable for P's oxidation state
Let oxidation state of P = $x$. Oxidation state of O = -2.
Step2: Sum oxidation states to ion charge
$x + 4(-2) = -3$
Step3: Solve for x
$x - 8 = -3 \implies x = +5$
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C. +5