Question

question 9 of 10
a softball diamond is in the shape of a square. the distance from base to base is 60 feet. how far does a catcher throw the ball from home plate to second base?
a. ( 30sqrt{2} ) feet
b. 30 feet
c. ( 60sqrt{2} ) feet
d. 60 feet

Explanation:

Step1: Identify the triangle type

The softball diamond is a square, so the throw from home to second base is the diagonal of the square. This forms a right - triangle with two sides of the square (each 60 feet) as the legs.

Step2: Apply the Pythagorean theorem

The Pythagorean theorem is $c = \sqrt{a^{2}+b^{2}}$, where $a$ and $b$ are the legs of the right - triangle and $c$ is the hypotenuse (the diagonal we want to find). Here, $a = 60$ and $b = 60$. So $c=\sqrt{60^{2}+60^{2}}=\sqrt{3600 + 3600}=\sqrt{7200}=\sqrt{3600\times2}=60\sqrt{2}$.

Answer:

C. $60\sqrt{2}$ feet